(2-x/x^2-4)-(x+1/x-2)=3

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Solution for (2-x/x^2-4)-(x+1/x-2)=3 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2-x-(x/(x^2))-(1/x)-4+2 = 3 // - 3

2-x-(x/(x^2))-(1/x)-4-3+2 = 0

2-x-x^-1-x^-1-4-3+2 = 0

-1*x^1-2*x^-1-3*x^0 = 0

(-1*x^2-3*x^1-2*x^0)/(x^1) = 0 // * x^2

x^1*(-1*x^2-3*x^1-2*x^0) = 0

x^1

-x^2-3*x-2 = 0

-x^2-3*x-2 = 0

DELTA = (-3)^2-(-2*(-1)*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)+3)/(-1*2) or x = (3-1^(1/2))/(-1*2)

x = -2 or x = -1

x in { -2, -1} 

x in { -2, -1 }

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